2=1.25w^2/3

Solution for 2=1.25w^2/3 equation:

2=1.25w^2/3

We move all terms to the left:

2-(1.25w^2/3)=0

We get rid of parentheses

-1.25w^2/3+2=0

We multiply all the terms by the denominator


-1.25w^2+2*3=0

We add all the numbers together, and all the variables

-1.25w^2+6=0

a = -1.25; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·(-1.25)·6
Δ = 30
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{30}}{2*-1.25}=\frac{0-\sqrt{30}}{-2.5}
=-\frac{\sqrt{}}{-2.5}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{30}}{2*-1.25}=\frac{0+\sqrt{30}}{-2.5}
=\frac{\sqrt{}}{-2.5}
$